Well, as far as I understand R-->R^2 functions it goes like this: h(t)=(3t, t) so in this example f(t) is 3t and g(t) is t. But obviously h(t) is not onto. And I'm sure that the solution is trivial, but for some reason I just can't see it. I'm not a mathematician so most of the things you've...
example of h: R-->R^2 such that h is onto
Hello everyone,
can anyone suggest an example of a function h: R --> R^2 such that h is onto. All I could come up with is the following:
h: R --> R^2 ==>
f(x) = y1
g(x) = y2
==> for h to be onto I need to find a function that gives me the...