Thank you! I ended up getting an answer.
I left flux as d\phi=\vec{B}Acos(\theta)d\theta where A is simply the area of the ring. Then, using an assumed angular velocity, I was able to cancel a bunch of stuff out that simplified the problem to \frac{dW}{dt}=\frac{V^2}{R}, V=-\frac{d\phi}{dt}...
Homework Statement
Our teacher isn't very descriptive:
A ring of radius "a" and resistance "R" is placed at the center of a long solenoid with "n" turns (assume the solenoid is longer and wider than the ring) with its axis lined up with that of the solenoid. Find the amount of work done to...