Recent content by Kloud

I got it thx. x=.054m

Yes but I can't use those equations cause the potential energy is 0. You said I can use the kinetic energy and the conservation of energy to find the springs compression x, but I just don't see how I can do it without including mgh, it also makes no sense to use because there is no displacement?

When you say start up you mean the KE that I calculated correct? If so then F=KE, sooo KE=-k*x where x=KE/k Correct?

Alright cool, I am just puzzled over the conservation of energy which is Ef=Ei, and I don't know what the equation will look like? I was thinking of sing F=-kx, but then I don't know how to find F? for the block.

Sorry for the double post, you can disregard my second question on what m and h are, I was thinking of something else. For the law of conversation of energy what will the equation be? The reason I am asking is because you said I should not have mgh in any of my work, so I'm not sure what to do?

Ok so since the blocks initial velocity is 0 I get the final velocity to be .633 m/s An then for the blocks Kinetic energy I get .18031joules? Are these answers good so far? Also for the conversation of energy the m will be the mass of the block and I assume h will be the springs compression...

Ok I got mgh=-mgx+(1/2)*k*x^2 since I don't have a value for h, cause the bullet is traveling horizontal the equation is mgx=(1/2)*k*x^2 x=((1/2)*k*x^2)/mg where k=121N/m-this is given This is as far as I got, cause at this point I am confused, cause if I had h, I would be able to solve this.

Homework Statement Its in the screenshot i took. I need someone to walk me through the process of solving this problem because I do not understand how to get the maximum compression distance x of the spring. I know that the momentum of the billet will= the momentum of the block. Homework...

Fn=P cause both forces is horizontal. @Parixit, so are you saying for part B, Fs=(9.8m/s^2)*(9.85kg), not Fs=Us*N? Cause the problem does not specify max static friction or not. I am confused now. How did we go from Fy=may to Fy=mg?, I know g is the gravitational acceleration, but if you change...

Ye your right, I am confused. I am pretty sure part b is correct cause the only equation I have for static friction is the max formula, while for part C I am kinda sure its correct cause initially we apply 515N to the book, so if I am getting 378.54, that's less force so I assume it to be the...

So the for part b would the friction force be fs=m*g*us?

Yes it is. Thats why I used the max formula. Part C on the other hand I am not sure about? What do you think about my answer for it?

Homework Statement Part C of problem Please see attachment : What is the minimum horizontal force needed to keep the book from slipping. Note that P=515N, and P=normal force, Fs=131.32N, Us=.255, M=9.85kg Homework Equations Fn=(m*g)/Us The Attempt at a Solution My answer is 378.549N, which...