So the integral is
E(0,0,1) = \frac{\lambda}{4\pi\epsilon_0}\int_{0}^{1}
\frac{(-t,-3t,1)}{(t^2+(3t)^2+1)^{\frac{3}{2}}}\sqrt{10}dt
right?
Does that mean that
E_{x}(0,0,1) = \int_{0}^{1}
\frac{-t}{(t^2+(3t)^2+1)^{\frac{3}{2}}}\sqrt{10}dt
E_{y}(0,0,1) = \int_{0}^{1}...
Thank you for the reply but I knew that was a vector:) Let me try an example to explain the details of my ignorance:
Compute the electric field at (0,0,1) due to a line of charge with charge density \lambda on the path c(t) = (t, 3t, 0) for t\in (0,1)
I know I can reduce this to a line of...
Hi,
I'm having some difficulty understanding the definition of an electric field.
When we define the electric field from a line of charge in terms of a path integral:
E(r)=\frac{1}{4\pi\epsilon_{0}}\int_{\mathcal{P}} \frac{\lambda(r')}{\Vert r-r' \Vert^{3}}(r-r')dl'
It seems to me that the...