Recent content by KnowledgeIsPower

Use F=Ma to find the acceleration due to the backward force. You can then find the time needed to reduce their speed to the correct value.

I have around 15 pages of the book to go and unfortunately came across an annoying problem where i am getting a slightly different answer to the book. Any help is appreciated. The question is as follows: A particle of mass m is suspended from a fixed point A by a light inextensible string of...

Sketch a speed time graph and calculate with the fact area = distance.

If a force is acting upwards or downwards from the point at which you are resolving, it is the horizontal (do not include vertical) distance to the force (so the point to measure to would be exactly above or below the force). multiplied by the force. Similarly, if a force is acting horizontally...

Alternatively you can use the four basic constant acceleration equations in a simultaneous equation i think.

Hmm, the link has gone down so I'm sorry i can't be more specific. If a force is acting upwards or downwards from the point at which you are resolving, it is the horizontal (do not include vertical) distance to the force (so the point to measure to would be exactly above or below the force)...

Animals eat animals. Why on Earth shouldn't humans? Being a vegeterian is simply politically correctness gone mad.

-Resolve horizontal forces. -Resolve vertical forces. -Resolve moments. Remember that if this is in equilibrium the force acting left and right must be equal. Forces acting up and down must be equal. The anti clockwise and clockwise moments at any given point must be equal. Where...

u = 20, v = 0 , t=10, a =? v = u + at 0 = 20 + 10a -20=10a a=-20/10 a=-2m/s/s. F=ma F=1000x2 F=2000N, opposing the motion of the car.

That looks tricky. Can't you cheat and use the trapezium rule with a large number of intervals? -_-;;

Hmm. I learned something from that too. Nice explanation.

Thanks for all the help and suggestions. I'll follow up some of the references and think about the posts. I think i may have to resit the chemistry module that i sat in May but with some hard work and thanks to your advice I'm sure i'll pass that one and the one i have to take next year.

But learning entirely from the lessons is impossible when your teacher cannot teach the content well. My Six form college isn't the best and my applied mathematics teacher for the last year was terrible. Basically, those of us who wanted to pass taught ourselves the content via the book...

That's what i meant. Now i can work it out for any angle. Thanks. Sorry for the bad wording, i'll have to look up how to use the mathematical notation sometime. In the book I am working out of Pi is usually left to the left of the integration sign and applied after the limited have been...

I got it and finished that chapter, thanks for the help. Deriving does help sometimes, if you can do it for that particular formula easily enough. An example is the double angle to single angle formulae - which are just based from sin(a+b) etc. Just a quick, small question on some integration...