Recent content by Kosovar

lim (n→∞) 1 + 3 + 5 + 7 + ... (2n-1) / (n+1) - [(2n+1)/2] first we find arithmetic sum: Sn=n/2*[2a1+(n-1)*d], where d=2, a1=1 lim (n→∞) n/2*[2+(n-1)*2] / (n+1) - [(2n+1)/2] lim (n→∞) n/2*[2+2n-2] / (n+1) - [(2n+1)/2] lim (n→∞) n(n) / (2n-1) / (n+1) - [(2n+1)/2] lim (n→∞) n^2/...