Ok. Firstly I wrote this:
Cu -> Cu2+ + 2e- (E0 = -0.34 V)
H2 -> 2H+ + 2e- (E0 = 0.00 V)
The following reaction was:
Cu + 2H+ -> Cu2+ + H2 (E0 cell = 0.34 V)
Next step:
0.3 V = 0.34 V - (RT / 2F) * ln ([Cu2+] / [10^-10])
Then I got:
3.11 = ln ([Cu2+] / [10^-10])
And for...
Hello,
I have a problem with this task:
"Water with pH 5 and reduction potential +0.30 V flows through copper pipe at 25 °C. Calculate how much copper dissolves (in ppm) in water due to corrosion of this pipe. Standard reduction potential of copper Cu0/Cu2+ is 0.34 V."
I spent lot of...