I tried to solve for sinθ and cosθ but I end up with to many unknowns.
T=tension
cosθ=2.4/T
sinθ=(3.5-h)/T
I tried to substitute for T. I got
tanθ=(3.5-h)/2.4
I still have two unknowns and only one equation.
Can you give me another hint?
I attached a file which shows the diagram. Maybe...
Homework Statement
Estimate the density of the water 5.7 km deep in the sea. (bulk modulus for water is B=2.0 x 10^9 N/m^2) By what fraction does it differ from the density at the surface?
Homework Equations
P=(rho)gh=F/A=B(delta l/l)
The Attempt at a Solution
So I have several...
Homework Statement
A 25kg object is being lifted by pulling on the ends of a 1.10mm diameter nylon cord that goes over two 3.50m high poles that are 4.8 m apart. How high above the floor will the object be when the cord breaks?
Homework Equations
F=EA
F=ma
The Attempt at a Solution
I...
Homework Statement
A uniform 6.0m long ladder of mass 17.0 kg leans against a smooth wall (so the force F_w exerted by the wall, , is perpendicular to the wall). The ladder makes an angle of 22.0 with the vertical wall, and the ground is rough.Determine the coefficient of static friction at...
Thanks. I got the first part. As for the second question, I'm not quite sure how to go about it. I think I'm suppose to use F=ma. So I caculated the acceleration.
a=(v^{2}-v^{2}_{0})/(2x)
a=(210^{2}-470^{2})/((2)(4))=-22100
F=ma=(940)(-22100)=-2077400
But that only gets me the force of...
Homework Statement
Early test flights for the space shuttle used a "glider" (mass of 940 kg including pilot). After a horizontal launch at 470 km/h at a height of 4000 m, the glider eventually landed at a speed of 210 km/h . What would its landing speed have been in the absence of air...
[b]1. A solid uniform disk of mass 21.0 kg and radius 85.0 cm is at rest flat on a frictionless surface. A string is wrapped around the rim of the disk and a constant force of 35.0 N is applied to the string. The string does not slip on the rim.
(A) When the disk has moved a distance of 3.2 m...
I understand now! Thank you for your help. I thought my answer for part A was wrong so I was too scared to submit it. But it worked out okay. By the way, how do I mark the thread as solved? Thanks again.
1. The radius of the roll of paper is 7.9cm and its moment of inertia is I= 3.1×10−3 kg m^2 . A force of 2.3 N is exerted on the end of the roll for 1.3 s, but the paper does not tear so it begins to unroll. A constant friction torque of 0.13 mN is exerted on the roll which gradually brings it...