- #1
kritzy
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Homework Statement
A 25kg object is being lifted by pulling on the ends of a 1.10mm diameter nylon cord that goes over two 3.50m high poles that are 4.8 m apart. How high above the floor will the object be when the cord breaks?
Homework Equations
F=EA
F=ma
The Attempt at a Solution
I thought that by using this equation, I could find the tension in the cord.
F=(500 x 10^6)(pi)(.00055)^2=475
X-dir force
Tcos θ + Tcos θ = 2Tcos θ=0
Y-dir force
Tsin θ + Tsin θ -mg=0
2Tsin θ=mg
I think my equations are incorrect. I didn't know how to account for the height and weight of the cord. Help would be much appreciated.