- #1

kritzy

- 12

- 0

## Homework Statement

A 25kg object is being lifted by pulling on the ends of a 1.10mm diameter nylon cord that goes over two 3.50m high poles that are 4.8 m apart. How high above the floor will the object be when the cord breaks?

## Homework Equations

F=EA

F=ma

## The Attempt at a Solution

I thought that by using this equation, I could find the tension in the cord.

F=(500 x 10^6)(pi)(.00055)^2=475

X-dir force

Tcos θ + Tcos θ = 2Tcos θ=0

Y-dir force

Tsin θ + Tsin θ -mg=0

2Tsin θ=mg

I think my equations are incorrect. I didn't know how to account for the height and weight of the cord. Help would be much appreciated.