Recent content by kscplay

You're solution is much shorter than mine. How did you do it? I don't know much about triangular numbers. I separated 1010100 into = 10002 + 1002 + 102. I noticed the pattern that n^2=a_{n}+a_{n-1} So then I proved that: [\frac{n(n+1)}{2}]+[\frac{(n-1)n}{2}]=n^2 Afterwards, it was easy...

That's a smart idea. Thanks ehild :)

Homework Statement Solve for x and y: x2 + (√8)x*sin[(√2)xy] +2 = 0 Homework Equations The Attempt at a Solution Other than decomposing the root 8 i don't know what else to do. any hints? thanks.

Thanks guys :)

lol :d

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I've further simplified it to: 4sin2x−tan2x−√3=0 Does this make it easier? Please help.

Not exactly because you're not doing the same operations on both the equations. You're multiplying 10 for the x^2 and adding 10 for the other. If you had done the same operation on both functions then the outcomes would have also been the same.

Homework Statement 2sin(4x)-sin(2x)-(√3)cos(2x)=0 x is [0,2π] Homework Equations The Attempt at a Solution Using trig identities: 8sinxcos3x-6sinxcosx-√3(2cos2x-1) Please help me with this problem. I have no idea where to go from here. Thanks.

Homework Statement -sin x = √3 * cos x where x is [0,2π] Homework Equations The Attempt at a Solution Would it be wrong to square both sides and then factor? sin2 x = 3cos2 x 1-cos2 x = 3cos2 x 0= 4cos2 x - 1 0 = (2cos x -1)(2cos x + 1) Now I solve the factors (2 solutions...

I just recopied the problem exactly as it was stated. But anyways I've already found the solution. Thanks :)

Homework Statement Which terms of this sequence add up to 1010100? (Don't need to be consecutive terms) {an}∞n=1 = {n(n+1)/2}∞n=1 Homework Equations The Attempt at a Solution The sequence is made up of the sums of all the numbers less than and including n. Don't really know much more...

Thanks, I get it now :) My final answer is 2. I just factored because I didn't really understand how SammyS solved for a & b.

Could you please elaborate on that? Thanks.

Okay, I get the following for x3: 20-6\sqrt[3]{10+6\sqrt{3}}-6\sqrt[3]{10-6\sqrt{3}} I still don't see it. Is my x3 correct? Thanks.