Recent content by kudelko24

Awesome... thank you! That was some what of a confusing question, but the more I looked into it, the more I understood it. Thanks again.

So the amount of work being done is 0, correct? Because Work = force * displacement * cos (). Cos = 1 because of the force being straight up and down, parallel. There's positive work being done and then that cancels out the negative work when he sets the weight back to the ground.

Thank you for the reply. I will look over the problem this weekend and can hopefully figure it out. Wish me luck. So for the second problem cos*90 because of the right angle from dead lifting the weight and it being perpendicular to the ground?

The spring of a spring gun has a constant of 6.0. It is compressed 0.0508 meters and a ball weighing 0.009 kg is placed in the barrel against the spring. a. What is the maximum speed of the ball as it leaves the gun? Vf = sqrt (k/m)x Xi = 1.31 m/s b. If it is shot off (horizontally) a 6...

y = Vyo X t - 1/2 a X t^2 20 = Vyo X 130m/(v0_x) - .5(-10m/s)130m/(v0_x)^2

Well, I'll try to work on this more this weekend. I'll be out of town until Sunday afternoon, so I'll take a look at it then. Thanks for all of your help. I'm determined to figure this problem out!

y = Vyo X t - 1/2 a X t^2 20 = Vyo X t - .5(-10m/s)t^2 Unknown again is initial velocity and time

ok well I'm confused... I have the answers in the back of the book to check my answers but that's not the problem. I want to know how to get those answers. If the equation x = Vo x t, then 130 = Vo x t. I still have 2 unknowns in this problem. The initial velocity and the time. I can't solve...

ok... so the initial velocity in the x direction is Vox = Vo X cos (theta). since you don't have the initial velocity it cancels out the cos (theta). Correct? Same goes with y initial velocity. Vo X .819 = Vox Vo X .574 = Voy

Help? Ok... well, a^y = -9.8 m/s^2 theta = 35 degrees y = 21 - 1 = 20 m, because of the ball being hit 1 m above the ground x = 130 m But you can't solve for the initial velocity or the horizontal/vertical components... how do i solve for the initial velocity? Or the time? Vo = x / t

Homework Statement A home run is hit in such a way that the baseball just clears a wall 21m high, located 130m from home plate. The ball is hit at such an angle of 35degrees to the horizontal, and air resistance is negligible. Find initial speed, the time it takes the ball to reach the wall...