Recent content by kunparekh18

Thank you! I still have a doubt, what if the gun was shot downwards? Then the y component of the gun would be in the positive y direction? What would I do then? Thanks in advance.

Bump?

Let the maximum height be h work done by gravity during upward flight = -mgh (-as force is opposite to displacement, cos180 = -1) work done by gravity during downward flight = mgh Net force = -mgh+mgh = 0 I don't know the exact expression for air resistance, but since it always acts against...

Thanks! I did consider the x and y components of the velocity of the center of mass separately. As you said, there is no external force acting along the x axis, so I can apply conservation of linear momentum there. 0 + 0 = Mv1 + mucosθ ==> v1 = -(mucosθ)/M So with that and my...

Work done is always force into displacement. As the object comes back to it's initial position, there is 0 net work on the body. So, I guess there is no work done by either force on the body. I may be wrong though, I'm not sure.

Hello everyone. First post here. I'll go the question straightaway. Homework Statement A gun of mass "M" placed on a smooth horizontal surface fires a bullet of mass "m" with a velocity "u" at an angle "θ" with the horizontal (ground). The velocity of the center of mass of the gun+bullet...