Recent content by Kyle52

So I can find the FOS with just the sheer loading force (sheer force/cross sectional area) and 60% of the 290MPa as the max stress? I don't need to use the tension force that it gives me? Sorry but this is confusing the hell out of me and it's probably so simple once you get it.

I believe that the shear stress area is the cross-sectional area of material with area parallel to the applied force vector. (This is what I have from my class notes) I think I'm just missing something as there seems to be more information given in the question than I need? Thanks for trying...

Thanks I now understand why it's single and not double. I'm strugling to understand the significance of the tension force and the tension force itt's telling me not to exceed in calculating the working stress on the bolt as the examples I can find online don't seem to have them. I can calculate...

Ok I think I might just be going crazy. This is a copy of the diagram that I have wth the question ( sorry about the paint skills I can't copy it from a pdf) As the shear is acting on both sides I asumed it was double sheer? Apart from this mis calcultaion are the steps I am going through...

I found it on a website that said to use 2 x pi r^2 if it is in double sheer which this is? but my tutor prefers us to use (pi d^2)/4 for area so I just put the 2 in front. This is incorrect I am guessing?

Homework Statement A Bolt is in single shear and is tightened so that it exerts a tension force of 39.886kN, the diameter of the bolt is 20mm and the shear loading is 26.276kN; Given that the tensile stress should not exceed 290MPa and the maximum shear stress should be taken as 60%...