Recent content by Kyrrus

566 m/s seem about right? Thats the speed leaving the cannon if I am correct. Which would also be 1267.2 mi/h ? Does it seem correct?

So should I convert the 20 miles to kilometers or meters and use it in the problem?

I ended up with 14.1 meter per second I believe? I took distance times gravity, then took sin (2 x 40) (yes I put it in like that not sure if I am right) then took the answer from D x G (196) and divided it by .985, ended up with 198.9 then square rooted that. Resulting in 14.1, but my physics...

Can anyone answer vietdao29's formula? Can you tell me what the formula is and actually solve it? I don't believe I am solving it right because for an initial velocity leaving the cannon I got 199 (not sure if its miles per hour or what).. Can anyone tell me exactly what I need to solve my...

Alright as I said I am totally lost right now, my physics teacher uses different variables so it seems different for me. Is it possible for someone to solve the equation for me and walk me step by step through it so I can understand it better?

Still completely and utterly lost, the horizontal velocity is a constant. 0-10 miles are spent going up while everything after 10 miles is spent goin down. Can anyone help me out some more?

This is a very important question, I need details on how to solve it step by step. A cannon on the Bismark German Battleship, fires a 2000 lbs (907kg) shell at an angle of 40degrees. It travels a distance of 20 miles (32.2km), what is the speed of the shell leaving the cannon? What is the...