Recent content by Laban

I sure hope you're both right. Thanks!

Hello :) I must have missed something. This problem is extremely simple and yet I can't figure out what I'm doing wrong. Really frustrating! The problem: A bucket of mass 6.75 kg hangs in a well at the end of a rope. The rope passes over a frictionless pulley at the top of the well, and you...

I just want to say a formal thank you... Thank you! :wink: You really got me out of a dire strait here. Looks tricky at first, but turns out to be really simple because it goes against the spontaneous common sense (of course i can only speak for myself, but i know my classmates had great...

So since the pulley is massless, the net force will be zero. Meaning T = ½F. That's what I thought from the very beginning, but my father talked me out of it (without knowing why) ^^ hehe

Hmm.. I tried this and ended up with negative acceleration for mass A. That should be impossible. The equation for the pulley looks like this \sum F_{y} = F - 2T = \left( m_{A} + m_{B} \right)\cdot a_{sys} where a_sys is the acceleration of the entire system. The equation for mass A...

You say "both cords", but we all know there is only one cord... which is why I'm getting confused. If there were two cords, and they were simply fastened to the upper rope without a pulley, then the downwards force in the free-body diagram for that junction of ropes would contain the sum of...

Those equations are two equations with two unknown variables. You found the acceleration by substracting one from the other. Now it's pretty easy to find the tension, since it is also part of those equations :)

The pulley is massless and so are the cords. Basically, I have a force F = 424 N and I need to find the accelerations of each block. To solve it, I gave block A an unknown force upwards + tension in the rope - weight. Block B I gave a different unkown force upwards + the same tension on the...

Look here Scroll down to "Standard Pulley Problem". I think it's all right there.

Hello, this is my first post here. I hope you can answer my current question, and that i will be able to answer other's questions later on! I have all the footwork (equations) under control, but I can't figure out how the forces are divided in this situation: There is a force applied...