Recent content by lam58

Hi, thank you very much for your help. So I tried the above with linear regression and on my calculator and I got pretty much the same answer for m and b like you predicted, however, it is still useful to know. Thanks again.

[SIZE=16px][FONT=Helvetica Neue] Hi again thanks for the reply. So I tried plotting everything and for question 1a) I got the sensitivity to be -0.0562 V. i.e. if, y = mx + b \Rightarrow m = \frac{dy}{dx} = \frac{(0.238 - - 0.0375)+(0.238 -...

OK, that seems to give me the same answer as i got in my second method. :frown:

Sorry, I'm confused by what you mean?

Hi, Thanks for the reply. OK, so does that mean I've done something wrong here? I'm sure I was supposed to work out the theoretical electrode response in part a) of the question? What about part b), any suggestions?

Hi, I'm stuck on part b) of the question below: Q: In order to perform pH determinations with a glass electrode, the cell potential was measured for threestandard solutions with the following pH values at 25 C: 2.04, 7.05, and 9.20. The cell voltage readout(in mV) for each of the above solutions...

Hello, I'm stuck on how to find the propagation velocity of the signal in the Line as stated in Question C on the attached image below. 1. Homework Statement Table one (in the attached image) shows typical values of Z and Y for an overhead line and underground cable. Please note that this is...

I appreciate both of your help, but I reckon I really need to study this more. I'm going to try and catch my lecturer tomorrow and ask. Fortunately this isn't homework, the unfortunate thing is this may potentially be a question in an exam I have in a few days. I'm an elec eng student and...

I know the answer is probably really obvious but I'm lost now. EDIT: I want to say this has something to do with helmholtz equation?

But isn't that similar to what I already had where \frac{\partial^2 E_x}{\partial z^2} = -j\omega^2 Ex \Rightarrow \frac{\partial^2 E_x}{\partial t^2} = \frac{1}{\mu \mu_0 \varepsilon_0} A_0 exp[-j \omega z]

Ok: \frac{\partial^2 E_x}{\partial t^2} = \mu \mu_0 \varepsilon_0 (- k^2 \varepsilon E_x) \Rightarrow E_x(z) = \mu \mu_0 \varepsilon_0 A_0 exp[-jkz] = 3\times 10^{16} A_0 exp[-jkz] Where k = \frac{\omega}{c} = \omega [\mu_0 \varepsilon_0]^{\frac{1}{2}}

Hi, thanks for your help. Going by what you say, I think then because \frac{{\partial {E_x}}}{{\partial z}}{u_y} = - \frac{{\partial B}}{{\partial t}} = -\mu \mu_0 \frac{ \partial Hy}{\partial t}, if I take the partial derivatives of both (one with respect to t and the other to z), I get...

Any suggestions?

Q) A harmonic time-dependent electromagnetic plane wave, of angular frequency ω, propagates along the positive z-direction in a source-free medium with σ = 0, ε = 1 and µ = 3. The magnetic field vector for this wave is: H = Hy uy. Use Maxwell’s equations to determine the corresponding electric...

For question 4b in the problem sheet attached below, is my working correct for B outside and inside the coaxial cable? Ans: Outside coaxial:∫B.dl = μI (the integral is between 0 and 2∏r) => B = (μI)/(2∏r) Inside the coaxial: \int_{2\pi a}^{2\pi r} B.dI = μI.\frac{a^2}{\pi...