Recent content by Lamoid

Shouldn't the function you plug in be of the form of a solution for a damped oscillation?

A cannon on a train car fires a projectile to the right with speed v relative to the train, from a barrel elevated at angle theta. The cannon fires just as the train, which had been cruising to the right along a level track with speed vt, begins to accelerate with acceleration a. Find an...

Just to clarify, I have no idea what I am talking about and should stop clarifying. I was right originally! It SHOULD be absolute x is less than root 2. You DO need need the radius to be in terms of x to the power of one. Live and learn. My apologies, I am watching a debate with creationists I...

Ok, well my instruction in my first post to remove the absolute value signs was dumb. If you take the root of both sides you get root of x^2 < root of 2. Remember that the root of x^2 is the absolute value of x anyway. So you see why what I told you was such a waste of time? To clarify, you...

Remember you have x^2 < 2. Just solve it for x. And about that absolute value thing, disregard what I said.

I think that should be x^2 < 2 actually. Since it will converge if x^2 / 2 is less than 1.Also, I don't believe you need to make it absolute value of x^2 since x^2 will always be positive.

So dv is pi*r^2*dx. Now, must I do anything to make the limits of intergration V1 to V2?

Okay, when I do that I end up, obviously, W = integral P * pi * r^2 * dx. I know I have to get V's in here, but I am unsure if I substitute pi * r^2 * dx with a V or a dv since I am talking about the change in x.

Hmm, so I am confused. This is my best guess. f * dx = W πr^2P * dx = W PV = W P*dv = W' Then you integrate it using the change in volume as the limits of integration?

Ok so that's the integral. So I replace (pi)(r^2)x with V ?

Integral of Force times distance

Homework Statement When gas expands in a cylinder with radius r, the pressure at any given time is a function of the volume: P = P (V). The force exerted by the gas on the piston is the product of the pressure and the area: F = π(r^2)P. Show that the work done by the gas when the volume...

If there were a job in medicine where you just got one very rare and difficult case a week, well, that would be awesome.

I don't know how people expect a test to quantify intelligence which is such an abstract thing. I can't remember who said it but IQ tests are very useful for determining who is good at taking IQ tests.

Simon, what college @ U of T are you at? I want to get a physics study group together.