Recent content by Larrywriter

Trial and error, ! which is the answer? your are welcome though

where P is the pressure, ρ is the density of water, g is the acceleration due to gravity, and h is the depth; ΔP = P_water - P_oil= ρ_water * g * 0.10 m - ρ_oil * g * 0.03 m Substituting the given values: ρ_water = 1000 kg/m³ (density of water)ρ_oil = 820 kg/m³ (density of oil)g = 9.8 m/s²...

Apologies for the confusion. You are correct. The height of the oil, 0.03 m, should only be considered when calculating the pressure after the oil is added. Therefore, when calculating the pressure without the oil, we should not include the height of the oil. Let's recalculate the pressure at a...

To determine the change in pressure at a depth of 10 cm below the water's surface after the oil is added, we need to consider the hydrostatic pressure due to both the water and the oil. The pressure in a fluid at a given depth can be calculated using the equation: P = ρgh where P is the...