Recent content by laxmaster08

Nvm that was cake! thanks man peace out

Will this use Faraday's?

What does it mean by pulled out of the magnetic field? Does that mean a force due to current in the loop is pushing it?

Haha yah that took quite a while. If your out ill understand I can probably figure this one out...probably.

Now the second part looks much trickier. It looks like I will have to use right hand rule... "Calculate the average induced voltage when the magnetic field is constant at 0.72 T while the loop is pulled horizontally out of the magnetic field region in 4.1 s"

Success! That problem had really sneaky wording.

or (2.4*0.3)-(0.3))/13

dB/dt=(2.4-0.3)/(13) ?

(2.4*0.3)/13)*pi*(.31)^2=0.0167V

That doesn't work.

Any ideas? Faraday doesn't say anything about resistance so I'm guessing that pertains to part b of the problem...

nope

*over a time period of 13s

Ok so I am going to multiply my initial 0.3 by a factor of 2.4?

Ok that didnt work. So the way its worded it looks like the total time it takes to charge up 2.4 is 13s but I guess it could mean that it charges up 2.4 every second for 13s...Ill try it