Recent content by learningcalc

that's brilliant! it's so obvious duh to myself haha! e^0 = 1. Thanks mate.

Personally I don't like to just give the answer when someone asks, but this is not one of those situation. So I know full well your intention Simon. Regards,

Hi Simon, Please understand I am not seeking approval nor am I trying to have someone else to just hand me the answer. I tried to use the comparison test to compare two series: e^(1/n))/n vs. e/n I know that e^(1/n))/n < e/n. So if e/n is convergent, then e^(1/n))/n must also be convergent...

Hi Simon, My question is whether or not I am approaching the question correctly and if my answer is justify. Thanks,

Homework Statement Determine whether the series converges or diverges Sum from n=1 to infinity ((e^(1/n))/n) Homework Equations I am trying to use the limit comparison test to prove it. The Attempt at a Solution an = (e^(1/n))/n bn = e/n an/bn = e^(1/n)/e lim n->...