Recent content by leezak

okay so i got that the angle is 34.44 degrees and that the force going up is (Normal force of the step)(sin34.44) right? am i then supposed to find the sum of the forces or something?

i'm not sure how to find that

the normal force from the step is acting horizontally towards the wheel and the vertical components are the weight (29 N) and the Normal force from the ground. what do i do with this info? do i somehow incorporate the torque equation?

The figure shows a bicycle wheel resting against a small step whose height is h = 0.110 m. The weight and radius of the wheel are W = 29.0 N and r = 0.350 m. A horizontal force F is applied to the axle of the wheel. As the magnitude of F increases, there comes a time when the wheel just begins...

The figure shows a bicycle wheel resting against a small step whose height is h = 0.110 m. The weight and radius of the wheel are W = 29.0 N and r = 0.350 m. A horizontal force F is applied to the axle of the wheel. As the magnitude of F increases, there comes a time when the wheel just begins...

A uniform board is leaning against a smooth vertical wall. The board is at an angle above the horizontal ground. The coefficient of static friction between the ground and the lower end of the board is 0.350. Find the smallest value for the angle , such that the lower end of the board does not...

i did and i still don't know what to do

The figure shows a bicycle wheel resting against a small step whose height is h = 0.110 m. The weight and radius of the wheel are W = 29.0 N and r = 0.350 m. A horizontal force F is applied to the axle of the wheel. As the magnitude of F increases, there comes a time when the wheel just begins...

A quarterback throws a pass that is a perfect spiral. In other words, the football does not wobble, but spins smoothly about an axis passing through each end of the ball. Suppose the ball spins at 7.04 rev/s. In addition, the ball is thrown with a linear speed of 21.6 m/s at an angle of 47.0°...

When jumping straight down, you can be seriously injured if you land stiff-legged. One way to avoid injury is to bend your knees upon landing to reduce the force of the impact. A 73.9-kg man just before contact with the ground has a speed of 5.55 m/s. (a) In a stiff-legged landing he comes to a...

For the work of F i multiplied F*h = F*30.66, for the work of the frictional force 545*30.66 = 16709.7, for the work of gravity m*g*sin7.34*30.66 = 54509.41, and then i added all those and set them equal to 203000 J (because its the net work)... and then i solved for F to get 4298.14... but...

A 1420-kg car is being driven up a 7.34° hill. The frictional force is directed opposite to the motion of the car and has a magnitude of 545 N. A force F is applied to the car by the road and propels the car forward. In addition to these two forces, two other forces act on the car: its weight W...

when then that would make the net force 0 and multiplying 0 by the velocity would make the power 0??

how do i find the force... we only know the force of air resistance... don't i have to find the force that propels the bike forward? I'm not sure how to find that

i'm still not getting this problem... i found that the work of kinetic friction is the work of F by using the h (since i found it from the distance) and then i broke the Work of gravity into x and y components and found the x component of the work of gravity. i then added all of the works...