Recent content by lemurs

Ok really dumb one here for you but for the life of me i can't remember. first e^(2lnx) is that equal to x^2 like i said brain fart thanks for the help guys

UGHHHH ! that the problem I not getting what the integral of that. I know i got to take the integral.. i just leave out the dr caue i know.. what the problem is that I have difficulty going in rever and thaking a integral of e^r/3

i understand the princple if integration by parts.. the formula abnd stuff is easy to me.. the one part i am having problem is whenI choice my dv. if dv=e^r/2 what the hell is v. that is my problem.. most often goiung back is the problem.

bah but like i siad i noit getting the right answere and i tried it several times... e^r/2 ' = e^r/2 *1/2 so dv = (e^r/2)/2 right?

i know this is integration by parts so here is the problem I am currently confused on how the get an answer r e^r/2 dr I know I the formula is int udv= uv - int du v what i am not getting is what to use for this one. I figured e^r/2 = v and du = r so u= r^2/2 and what...

ok just want to m ake sure I get this. to solve the sin (2@) you used an Identity that sin 2@ = 2sin@cos@ and you can find cos cause we know what sin is. correct?

whawt was I supposed do then.. as far as i know i should use the fact that cos @^2 =1/2(1+cos 2@) if i did that wrong then what is the correct way?

Ok guys here we go. this isI just a suggested question from our teacher in prep for our final. it a integral one. trig substion the prob I am having is near the end.. all the substition works great was down to the last bit and for some reason I must be doing the back substition wrong. so here...

ok i understna what you wrote neutrino so i but i got that 3 out front so with the little identity bit wuld it be 3(1/2(cos(a-b)+cos(a+b)))

ok.. title says it all I feeling really stupid right now and seem to be having trouble with elementary stuff here.. given r= sin 3x dr= cos 3x * 3 dx i got that . but next step in the equation i am doing is 3cos 3x * cos x as i said feeling stupid si it 3 cos^2 3x?

given x^2-y^2=1 find the parametric equation... i have no clue where to start... it looks like a cirlce equation but i know that not right so what the hell?

ok i understnad that now but how would you do the reverse.. go form given a cartesian equation to a cause given X^2-y^2=1 how would you solve that

so then i would justs substiute in those in so it would be x^2/16 +y^2/25

ok I am give a parametric equations of x= 4 cos t and y=5 sin t I know that i have to solve the x equation for t then stick it in the y equation but i getting stuck or not rembering some simple stuff i should be. I believe i get t= cos(inv) (x/4) and substiute it into t in y. if so...

ok.. but how.. not making sense. I how would I jsutiify p(k+1) - P(K). that is not as easy..