Recent content by Lfrizz

I'm guessing it's meters per second, but where do the radians go? And why do we not use meters per radian per second? Just delving too far into this tonight...

Just calculated the Tangential speed that music is detected from a CD. I found it using Vt=r\omega where r was in meters and \omega I converted from revolutions per second to radians per second. What unit of measure is tangential speed in? Thanks, Leah

yayyy

:) thank you, that helped alot- I found \theta=arccos(1/4) because 2\pir (cos\theta)/t =1/4 2\pir/t it came out to be 75.5 degrees

http://edugen.wiley.com/edugen/courses/crs2216/art/qb/qu/c08/ch08p_33.gif

Now I went and confused myself b/c I wasn't using the tangential variables... I THINK I need to divide v/4. and I am confused how to get back to theta.

The Earth has a radius of 6.38 x 106 m and turns on its axis once every 23.9 h. (a) What is the tangential speed (in m/s) of a person living in Ecuador, a country that lies on the equator? (b) At what latitude (i.e., the angle in the figure, in degrees) is the tangential speed 1/4 that of a...

that makes more sense.

What is the easier way? lol

It says I got it right... Wow Thanks! \omega=2\pi/60sec = .105 w = θ/T .105=3.16/T T= 30.09 THANK YOU!

I think I might get what your saying... 2\pi/60 would give me \omega then I can plug in 3.16 from my previous post for \theta and solve for T ?

I'm still confused how I find the T of just that one small portion of the rotation. Sorry if I seem dense, I read to much into these problems. And thank you for your help! T for the second hand to make an entire rotation is 60 sec the radius of the entire rotation is .06m the arc length is...

I messed up. r=.06 not 0.19.

I think it would = 2\pir. So... I will use the formula w = θ/T Where \theta= 2\pir and r=0.19m divided by T=60s to find omega \omega (I'm still trying to get familiar with the little reference list on the side, I'm going blind) Then I use this Omega with the theta I found above and...

I think I might be on to something... the t for the entire radius should be 60 seconds... so would I divide .06m/60s to get the avg. angular velocity? Then I could use that with the theta I find for the arc length of .19m to find the time for that distance?