Recent content by liiamra

Thanks Tiny-tim, The actual equations I am trying to equate are pretty large, and apparently there must be a trick to calculate the variable (found in one of the two equations) - most probably it should be a closed form solution. So far, I don't think there will be a solution and so I thank...

Thanks Tin-tim, No, suppose I have the following two equations: x=\sum^{N}_{t=1}\beta^{t}{C(1-g)^{t}-\beta^{t}} y=\sum^{N}_{t=1}\beta^{t}{C(1+k)^{t}-\beta^{t}} I want to calculate \frac{x}{y}, and in the process I need to eleminate C as I don't have its value. Any ideas? Thanks...

Hi again, The last equation is not equivalent- but the problem, after factoring the (1/1-α) out, can be expressed as: \sum^{N}_{t=1}\beta^{t}{C(1-g)^{t}-\beta^{t}} where I need to get the constant C out. Regards

Thanks again, but suppose I have the following which can serve as a perfect simplification of the problem: Ʃa^t*C - a^T your answer suggests that it becomes ƩC(a^t*C - a^T) and this is not a solution- beside, indeed the denominator can be factored out but I am interested in factoring the C...

I don't know if I got you right! because: - I don't want to end up with c*(cƩ-Ʃ) which is nothing really - Further, 3*2-3*1 are not the same as 2-1 Thanks anyways for the post

Just as a quick add: I think that if I simplify to: \sum^{N}_{t=1}\frac{\beta^{t}C(1-g)^{t}}{1-\alpha}-\frac{\beta^{t}}{1-\alpha} I could get the C constant out, but the only problem is that I will end up with: C\sum^{N}_{t=1}\frac{\beta^{t}(1-g)^{t}}{1-\alpha}-...

Hello All, I have what I think an easy summation, but I haven't worked with math for very long - I don't know the term which I should search the internet for in order to solve the problem and so I would be very thankful if you help me get the constant C out of the summation...