i thought of another way of doing it which relates to the chart
consider x and y to be 2 different modes between 1 and 8
then
(2.654)(x^2)=(4.147)(y^2)
x/y=srt(4.147/2.654)
x/y=1.25
x/y=5/4
meaning that the linear density is equal at mode 5 and tension 2.654 to the linear density at mode 4...
ok so would this be a correct way of approaching it?
by combining f=mv/2L and v=srqt(T/u)
m being the mode, T being the tension and u being the linear density
we can derive u=(T)(m^2)/(2Lf)^2
with the values given we have
u=(T)(m^2)/82944
Now I make a table
------T=2.654N-------T=4.147N
m=1...
yeah i understand what nodes are and also looked through the link. I also understand that a standing wave can exist on a string only if its wavelength can be given by the equation:
wavelength= 2 x length of string / m
m being an integer >0 and also the mode of the string
the mode in this case...
A string of fixed length L=1.200m is vibrated at a fixed frequency of f=120.0Hz. The tension, Ts, of the string can be varied. Standing waves with fewer than seven nodes are observed on the string when the tension is 2.654N and 4.147N, but not for any intermediate tension. What is the linear...