Recent content by littlemayhem

Thank you! Okay: L = r x p = r p sin \theta where sin 90 = 1 so L = rp & p=mv so L = rmv and v = \omegar so L = r^{2}m\omega if we equate {r^{2}m\omega}_{initial} and {r^{2}m\omega}_{final} and cancel the mass (which stays the same), we get r^{2}_i * \omega_i = r^{2}_f * \omega_f with...

Homework Statement A particle on a string at radius r=0.22m is moving in a (horizontal) circle with angular speed \omega =0.55 rad/s. The string is shortened to 0.15m. Show that the new angular speed is 1.18rad/s Homework Equations v = r\omega a = \omega^{2}r a = r\alpha...