Recent content by lizaliiu

  1. L

    How far is the ray displaced as a result of traveling through the gla

    1. A ray of light passes from air through dense flint glass and then back into air. The angle of incidence on the first glass surface is 63.5°. The thickness of the glass is 4.26 mm; its front and back surfaces are parallel. How far is the ray displaced as a result of traveling through the...
  2. L

    What is the maximum instantaneous power that the resistance must withs

    1. A hair dryer has a power rating of 1700 W at 110 V rms. Assume the hair dryer circuit contains only resistance. 2. The peak voltage is sqrt2 * rms voltage. 3. I got my esistance of the heating element is 7.12ohm and the rms current drawn by the hair dryer is 15.45A. But I am...
  3. L

    What is the induced emf in one of the windings?

    N=how many turns L=length of the wire?!
  4. L

    What is the induced emf in one of the windings?

    1. A solenoid of length 3.64 cm and diameter 0.914 cm is wound with 170 turns per cm. If the current is decreasing at a rate of 36.3 A/s, what is the induced emf in one of the windings? this is what I did: Length of the solenoid l = 3.64cm = (3.64...
  5. L

    Proton Suspension Between Horizontal Parallel Plates: Charge & Voltage

    yes, I solved V= 2.66x10^-10...not positive sure it's correct tho
  6. L

    Proton Suspension Between Horizontal Parallel Plates: Charge & Voltage

    since gravity pulls the proton downward so the lower plate should be the positive charge to repel the proton. F=mg=qE E=mg/q=v/d, m=1.673x10^-27kg, g=9.8m/s2, q=1.602x10^-19 and d=2.60x10^-3m so we just need to solve q to get the voltage across the plates?
  7. L

    Proton Suspension Between Horizontal Parallel Plates: Charge & Voltage

    1. A proton is suspended in a vacuum between two oppositely charged horizontal parallel plates. The separation between the plates is 2.60mm 2. I assume it uses E=vd/d, but I don't really know 3. what is the sign of the charge on the lower plate? what is the voltage across...
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