let f(x) = 1 when x in in [0,1)
f(x) = -1/2 when x is in [1,2)
f(x) = 1/3 when x is in [2, 3)
and so on, in othe words its the sequence (1/n)(-1)^n, whose series obviously converges to log 2. However is f(x) Riemann integrable and equal to this series?
If so, how to give an...
Right, that is what I thought, since its a removable singularity, the residue at zero is zero, then the integral of that function is zero.
thank you everybody
Thank you for the replies, but this is no where near as complicated.
y=e^(2(pi)(i)(t)) 0=<t=<1 is indeed a closed contour, since e^(2(pi)(i)) = e^0.
My question was am I right in assuming that the function is analytic (equivalently differentiable) on the domain inside the contour, if it...
Hi,
Does this complex contour integral equal 0?
[Int] (z^2)/(sin z) dz along the closed contour e^2(pi)(i)(t) 0<t<1
It should equal zero cause its analytic in the domain around te curve and the zero in the numerator is of higher order than the zero in the denominator at the point z=0...