Recent content by ll-Angel-ll

thank u thank u thank u i can't believe that i solved it actually i couldn't solve it without u thank u thank u thank u ok and now i'll check 2 log {base x} of 5 + log {base 5} of x = log 1000 2 log {base 5} of 5 + log {base 5} of 5 = 3 2 * 1 + 1 = 3 2 + 1...

ok if log {base 5} of x =1 then x = 5 and if log {base 5} of x = 2 then x = 25 am i right ?! :shy:

:frown: i think the teacher was telling me the truth when she said I'm stupid 2 log {base x} of 5 + log {base 5} of x = log 1000 [2/ log {base 5} of x] + log {base 5} of x = 3 L = log {base 5} of x 2/L + L = 3 2+L^2 = 3L L^2 - 3L + 2 = 0 ( L-2 ) ( L -1 ) = 0 L = 2...

cool I'm making progress ok 2/L+L=3 first we multiply both sides by 1/2 so it will be L+L = 3/2 2L = 3/2 so L = 3/4 am i right ?! :shy:

ok i think i got it 2 log {base x} of 5 + log {base 5} of x = log 1000 [2/ log {base 5} of x] + log {base 5} of x = 3 ok then i should ummm .. [2 (log {base 5} of x) (log {base 5} of x)] / log {base 5} of x =3 2 (log {base 5} of x) =3 so (log {base 5} of x^2) = 3 am i...

ok so 2 log {base x} of 5 + log {base 5} of x = log 1000 2 / 2 log {base 5} of x + log {base 5} of x = 3 2 / log {base 5} of x^2 = 3 2 / 2 log {base 5} of x = 3 1 / log {base 5} of x = 3 log {base x} of 5 = 3 right ?! :biggrin:

ok so u'r saying that what i did was correct that 1/x = 2 but x doesn't equal 1/2 right ?!

ok i think i got it but don't laugh if it's wrong 2 log {base x} of 5 + log {base 5} of x = log 1000 1/( 2 log {base 5} of x ) + ( log {base 5} of x )/1 = 3 1/( 2 log {base 5} of x ) + (( log {base 5} of x )( 2 log {base 5} of x ))/( 2 log {base 5} of x ) = 3 so ( log {base...

Hi I really need ur help I was sick in the days that the teacher gave us the lesson and I really really need ur help this is the equation : 2 log{to base x} of 5 + log{to base 5} of x = log 1000 i know that log 1000 = 3 and 2 log{to base x} of 5 = log{to base...