Yea I understand what you mean now. Sorry about that.
The problem I am really facing with this problem as evident by my attempt at the solution in post number 4. The question asks to find the angular acceleration, do I just give it as α? or do I derive that from other variables stated in the...
bump
Here's my working so far:
Angular acceleration is the same for both discs = α
=> acceleration of mass 1 = αR and mass 2 = αr
I then drew free body diagrams of the 2 masses with mass 1 on the left and mass 2 on the right.
Fnet=ma
T1 - Mg = M(a1) - eq.1
T2 - Mg = M(a2) - eq.2
eq1-eq2...
So if I assume that the discs have no mass, we are also neglecting the gravity? I think I am missing something here.
I just find it difficult when a question does not give me any quantitative value to work with.
I appreciate your help.
Homework Statement
Two discs of radius R and r are fixed to each other, i.e., they rotate
together. Strings are wound around both discs and two equal masses M
are connected to the ends of the strings (see Figure 1). Find the angular
accelerations of the discs, the accelerations of the masses...
So using 2)
for both balls it becomes:
X = 0 + 0(t) + 1/2(a)(t^2)
X = 1/2(a)(t^2)
t^2 = X/(1/2a)
Since XA < XB and aA < aB ...
It seems like I have hit another sticking point.
Ahhh. Thanks for correcting me, it is indeed a force.
So the only constant acceleration equation that is independent from time is v2 = v20 + 2ax
I will continue from here and update on my progress.
Thank you.
Homework Statement
Two balls A and B simultaneously start to roll down without friction along
two different chords of a circle as shown in the figure. Find which ball will
hit the circle first? (image attached)
2. The attempt at a solution
I have divided the velocity of the balls into vector...
Homework Statement
an = [sin(n)]/n
Prove that this sequence converges using Cauchy theorem
Homework Equations
Cauchy theorem states that:
A sequence is called a Cauchy theorem if for all ε > 0, there exists N , for all n > N s.t. |xn+1 - xn| < εI do not know how to approach this proof.
I...