What about the experts? I joined this forum hoping that some of the more advanced physics students could enlighten me in a situation like this. Well, for those who posted here, thanks anyway. At least I know someone somewhere in the world got the same answer as me.
Yeah but the bomb goes down and causes the displacement to be negative since it is 4000m below the initial point of drop. I really need to know if the bok's answer is correct or is it wrong. My physics teacher got 287ms-1, one of my classmates got 264ms-1 using an unorthodox method of vector...
Oh sorry for my initial post stating that I used u=0. That was for a different question. I got my workings messed up as I hurriedly tried to find them after I found out that you need to post your workings.
I used u = 50sin30 = 25ms-1 and subbed it into s=ut+1/2at^2 to get t.
When a aircraft is 4000m above the ground and flying upwards with a velocity of 50 m s-1 at an angle of 30° to the horizontal. A bomb is released. Neglecting air resistance, calculate
a) the time taken by the bomb to reach the ground,
b) the velocity of the bomb when it strikes the ground...