The question reads:
A farmer purchased 100 head of livestock for a total cost of $4000. Prices were as follow: calves, $120 each; lambs, $50 each; piglets, $25 each. If the farmer obtained at least one animal of each type, how many of each did he buy?
I obtained that -240 < t < -15.789 but...
Okay I guess I am just stupid then. Where exactly do you type \sqrt{2 a_n} ? I thought it was to surround it by CODE tags but that didn't do it and I tried typing it just by itself, with and without the \. What do I do then?
Thanks I got it from that. But can someone tell me how to do the root thing? Is the code LaTeX code or what is it?
Also, how can I prove the limit of that sequence = 2?
Is there some theorem that says that the limit of an increasing bounded sequence is equal to the sup of that sequence?
Hey guys,
I have a sequence, \sqrt{2}, \sqrt{2 \sqrt{2}}, \sqrt{2 \sqrt{2 \sqrt{2}}}, ...
Basically, the sequence is defined as x1 = root 2
x(n+1) = root (2 * xn).
I need to show that this sequence converges and find the limit.
I proved by induction that this sequence increases...
And if all else fails for closure, you could list all the combinations of the elements and show that they each give you something back in Un. Although that would be the REALLY long way to go.
I need to show that this is an algebraic number.
In other words,
I need to show: an*x^n + an1*x^(n-1) + ... + a1 * x^1 + a0 * x^0 =
where the a terms are not ALL 0 but some of them can be.
Like for root 2 by itself,
I have 1 * (root 2) ^ 2 + 0 * (root 2)^1 + -2 * (root 2) ^ 0...
I need to show that this is an algebraic number.
In other words,
I need to show: an*x^n + an1*x^(n-1) + ... + a1 * x^1 + a0 * x^0 =
where the a terms are not ALL 0 but some of them can be.
Like for root 2 by itself,
I have 1 * (root 2) ^ 2 + 0 * (root 2)^1 + -2 * (root 2) ^ 0...
I need to show that this is an algebraic number.
In other words,
I need to show: an*x^n + an1*x^(n-1) + ... + a1 * x^1 + a0 * x^0 =
where the a terms are not ALL 0 but some of them can be.
Like for root 2 by itself,
I have 1 * (root 2) ^ 2 + 0 * (root 2)^1 + -2 * (root 2) ^ 0