Right, right. That rule would make those very easy! Thanks bud! :-p
I am still having trouble with the cosine one however. I apparently need to use multiple steps to find the derivative.
Ok good! That is what I thought.
You have been so helpful! Thanks!
I have a couple more [shorter] questions, however don't feel obliged to respond if you don't want to...
1. Find dy/dx of y = x^5 * 7^x
2. Find dy/dx of y = (1/2) ^ x
3. Find dy/dx of y = (cosx) ^ x
Ok, right.
So
2x = ln (sin(x+3y))
Then if you take the derivative...
2 = (1/sin(x+3y)) * cos (x+3y) * 3 * dy/dx
So dy/dx = 2(sin(x+3y))/ 3(cos(x+3y)) ?
Is that right?
I need help with this problem.
Find dy/dx if e^2x = sin(x+3y)
Any help would be great!
I began by taking the natural log of both sides...which may not be correct??
Thanks!