Well, if I was standing and pushing "down" on the book at a 30 deg angle, it is my understanding the force would still be acting from above the surface of the table. If this is not the case then the wording is fine. Ambiguous or not, I'm happy for the help.
The wording in question:
"A...
Thank you for everyone your help. The applied force is acting up as you suggested.
"A different force of F = 3 N now acts on the book at an angle of θ = 30 deg above the surface of the table." I can see this being read two ways. What it tells us for sure is that the angle is 30 deg when...
How I am reading it is the force acts downwards. In my picture down and to the right. Since there is no acceleration in the y direction, Fy+mg = N. Fy and mg act down and N acts up. Is this correct?
[SOLVED] Kinetic and Static Friction
I've done so many of these but for some reason can't figure this one out. Any help iwll be greatly appreiciated. Here is the problem:
A book of mass M = 0.55 kg rests on a table where the coefficient of static friction μs = 0.48. What is the minimum...