Recent content by LuculentCabal

Sorry guys, but I have no idea how to find v if all that I know is y(x), g, mu_k, and the initials v0, x0. It seems v cannot be found without first either knowing x(t) or F_x(t) and neither x(t) or F_x(t) can be found without knowing v...

Hello haruspex. Thank you for your review. Yes, \vec{F_\bot}is due to gravity. I would be grateful if you (or someone) could explain why our mass would experience acceleration normal to the curve on the points where \frac{d^2 y}{dx^2} ≠ 0. I had imagined that at the point (x,y), our...

Thank you for taking the time to offer your suggestions WraithGlade. Unfortunately the problem with the model that I have presented is that displacement instead of distance was used for the purpose of determining theta. It is because of this that I am getting signed angles which are problematic...

Well it seemed like a good idea, but it appears as though we can't have signed angles ie θ ≠ tan^{-1}(y') but rather θ = |tan^{-1}(y')| = tan^{-1}(|y'|)

Hi willem2. Thanks for pointing that out. In trying to find out why that is the case, I found an angle error in my derrivation of the force of friction. I hope this is the only bug...

For a unit mass sliding down the stationary curve y = f(x) at the point (x, y), we can consider our mass to be sliding down a stationary inclined plane which is tangential to the curve at the point (x, y). The slope of this inclined plane is thus \frac{dy}{dx}(x). For the remainder of this...

A little more complex would be the following system which factors a quintic when a, b, c, d, e, f, g, h, i and j are solved for with A, B, C, D, E, and F being constants. acegi = A acegj + acehi + acfgi + egadi + egbci = B acehj + acfgj + egadj + egbcj + acfhi + adehi + adfgi +...

Thanks for the output MikeyW, your MATLAB solution looks consistent with what I have found. I have found that the system can be simplified to a function of b, c, and the constants. Letting one of the variables assume any value, I can solve for the other with the quadratic formula or Newtons...

Could there still be numerical methods for finding the solutions? Thanks for your reply.

Basically I have the following system: ac = A ad + bc = B bd = C where A, B, and C are constants. Solving for a, b, c, and d, what kind of problem/system am I encountering and what appropriate tools (vectors and/or numerical methods perhaps[?]) would help to find the set...

I am defining N as being the length of a set of characters where the length of the set is random (hence rolling a die to determine the number of sides on a die to roll), but I think we are both agreeing on the same thing. As I have said, I have no formal training in any of this and perhaps N...

OK, I am starting to confuse myself here. //-------------------------------Begin Brain Storm---------------------------------- Letting L = 1: If N were a six-sided fair-die throw, there would be six possible outcomes so N would be six. In this case, H would just be 2.59. However, if you threw...

Thank you john creighto. Can you explain a bit further. Assume that N was representing the throw of a six sided fair die. Are you saying that log_2 (N) would be a discrete random variable with possible values {log_2 (1), log_2 (2), log_2 (3), log_2 (4), log_2 (5), log_2 (6)}? This would seem...

Thank you sir/madam! This is precisely what I needed to know in order to move on to the next phase (aside from the logarithm thing which was covered earlier). Any future questions (of mine) regarding this information will be topics for other threads. Thanks again :approve:

Precisely. The entropy of any four toss sequence would be four bits: H = \sum^{I = 4} _{i = 1} log_2 P(h_i) Where H is entropy in bits, i is the toss in the sequence, I is the sequence length, P(h_i) is the probability of getting heads. So H = 4 log_2{1/2} = 4 * 1 = 4 So again I...