Recent content by lvuongt

Sorry forgot to put my attempt, P(E)=1eE/kBT−1 ------------(1) from eq. 1, P(E1)=1/4 and P(E2)=3/4 E1=kBTln(5) E2=kBTln(7/4) hence DeltaE=E1−E2=kBTln(20/7)=1.0498 kBT I was sure if this answer was okay since the distribution include the chemical potential as well.

Based on Fermi distribution, if there are two electron energy levels with occupation possibility of ¼ and ¾, respectively, calculate energy difference between these two levels.