Perpindicular neutrino travel
The main part I am not understanding is how to deal with the perpendicular travel of the neutrino. Since E=K+E0=K+mc^2 and the neutrino is massless this means that E=K=.300MeV. How do I deal with this in the perpendicular direction?
moondog
My results so far...
For part a I calculated a kinetic energy of 0.782MeV for the electron and 0.752keV for the proton.
For part b I calculated a kinetic energy of 0.483MeV for the proton and 0.387keV for the proton.
Lastly, for part c I calculated 1.08MeV for the electron and 1.21keV for the...
A neutron at rest in the laboratory spontaneously decays into a proton, an electron, and a small essentially massless particle called a neutrino. Calculate the kinetic energy of the proton and the electron in each of the following cases:
a) the neutrino has no kinetic energy
b) the neutrino...
What I have so far
For S frame:
x'a = (0 -u*a)γ=0 x'b = (2400-u*5E-6)γ
y'a = 0 y'b = 0
z'a = 0 z'b = 0
t'a =(0-u/c^2*0)γ=0 t'b = (5E-6-u/c^2*5E-6)γ
Is this a good start or have I missed some fundamentat concept?
moondog
I need help with this one...
Observer S notes that two colored lights, separated by 2400m, occur at positions on the +x-axis of his reference frame. A blue flash occurs first, followed after 5.00μs by a red flash. The red flash is farther away from his origin than the blue. Another observer...