Recent content by m00nd0g68

Perpindicular neutrino travel The main part I am not understanding is how to deal with the perpendicular travel of the neutrino. Since E=K+E0=K+mc^2 and the neutrino is massless this means that E=K=.300MeV. How do I deal with this in the perpendicular direction? moondog

My results so far... For part a I calculated a kinetic energy of 0.782MeV for the electron and 0.752keV for the proton. For part b I calculated a kinetic energy of 0.483MeV for the proton and 0.387keV for the proton. Lastly, for part c I calculated 1.08MeV for the electron and 1.21keV for the...

A neutron at rest in the laboratory spontaneously decays into a proton, an electron, and a small essentially massless particle called a neutrino. Calculate the kinetic energy of the proton and the electron in each of the following cases: a) the neutrino has no kinetic energy b) the neutrino...

gamma I have solved the Δx' equation and have: v=(x'-Δx*γ)/(Δtγ) Now how do I find gamma? This is where I am stuck... moondog

What I have so far For S frame: x'a = (0 -u*a)γ=0 x'b = (2400-u*5E-6)γ y'a = 0 y'b = 0 z'a = 0 z'b = 0 t'a =(0-u/c^2*0)γ=0 t'b = (5E-6-u/c^2*5E-6)γ Is this a good start or have I missed some fundamentat concept? moondog

Thank you I appreciate the hint. I will post what I have later. moondog

I need help with this one... Observer S notes that two colored lights, separated by 2400m, occur at positions on the +x-axis of his reference frame. A blue flash occurs first, followed after 5.00μs by a red flash. The red flash is farther away from his origin than the blue. Another observer...