Recent content by mabster

Brilliant! That all makes sense to me now! Thanks heaps!

Thanks! What you're saying makes sense, but I'm still missing the "intuition" here (this seems so fundamental that I should already know this). My problem is that the bottom rail is electrically common, so this should be an equivalent circuit: Which to me would act like resistors in...

Thanks, that's a really good point phinds! That's the kind of thing that will lose marks during the exams. I'll need to curb that :) ! Much appreciated!

Under steady-state condition (t=\infty), the capacitor will act as an open-circuit. KCL at B: I_1=-0, so I_1=0\,\mathrm{A} KVL around right-hand loop: v_c(\infty)=I_1(100\times 10^3)=[0](100\times 10^3)=0\,\mathrm{V} I'm not sure if there's typically a differential equation argument for...

Homework Statement Prior to t=0, switch is in position A (for long time). Afterward, switch is in position B. We need to derive the equation for vc. Homework Equations v(t)=v(\infty)+[v(0)-v(\infty)]e^\frac{-t}{\tau} \tau=RC The Attempt at a Solution at t=0...