Thanks! What you're saying makes sense, but I'm still missing the "intuition" here (this seems so fundamental that I should already know this). My problem is that the bottom rail is electrically common, so this should be an equivalent circuit:
Which to me would act like resistors in...
Thanks, that's a really good point phinds! That's the kind of thing that will lose marks during the exams. I'll need to curb that :) !
Much appreciated!
Under steady-state condition (t=\infty), the capacitor will act as an open-circuit.
KCL at B: I_1=-0, so I_1=0\,\mathrm{A}
KVL around right-hand loop: v_c(\infty)=I_1(100\times 10^3)=[0](100\times 10^3)=0\,\mathrm{V}
I'm not sure if there's typically a differential equation argument for...
Homework Statement
Prior to t=0, switch is in position A (for long time).
Afterward, switch is in position B.
We need to derive the equation for vc.
Homework Equations
v(t)=v(\infty)+[v(0)-v(\infty)]e^\frac{-t}{\tau}
\tau=RC
The Attempt at a Solution
at t=0...