Hi Rude Man, thanks for the reply.
In a) they ask for the laplace form of the input portion of the circuit, but they give Ip(s)=Ks(delta)x(s) in the text
Have they not given me what they are asking for? or am i looking at it wrong?
In terms of the output I am looking at the formula V=1/c...
Homework Statement
FIGURE 4(a) represents a system to measure acceleration (i.e. an accelerometer). It shows a piezoelectric crystal that is connected to an amplifier and display via a length of coaxial cable2.A piezoelectric current is produced when the crystal is distorted by an applied...
One theory I have is when I use the trig rule, I change the sin(x) of the bn function to a cos then when I integrate it goes back to a sin, after integration should bn= (something) cos(something)?
Hi Guys,
I am really struggling with this same question, here is what I have done so far, but there is a mistake (a few probably) in there and I can't find it!
fx=Vsin (wt)
x=wt
So a0= 1/π∫f(x)dx
= V/π∫sin (x) dx [lim π/2 to π] + V/π∫sin (x) dx [lim 3π/2 to 2π]
So next I integrated the...
Your final answer is different to mine, looking at V20(0.75+j0.05)=67.071+j30, you have a sign different somewhere in the build up to this.
I don't want to post exactly what as I am new to the forum and I could be wrong and I am not sure what is acceptable to post in regards to solutions.
In...
Hi gneil,
thanks for the reply.
In Mesh one I have tried to justify my thinking but see the error now, thanks.
In mesh two I put Vz4 as a positive as I think the +ve term would be at the top of z4. I started top left of the mesh and walked clockwise, -v3 as I come to the + side first, same...
Hi Folks,
Sorry to revive an old thread but I am on the same unit and the notes are not helping me much!
What I have so far is -
Mesh 1
V1-(Vz1)-(Vz4)=0
V1-(I1Z1)-((I1-I2)Z4)=0
V1-I1(Z1-Z4)+(I2Z4)=0
120-I1(2+j5)-I2(-j5)=0
Mesh 2
-V3-Vz5+Vz4=0
-V3-Z5(I2-I3)+Z4(I2-I1)=0...
Hi Folks!
I'm new, found this site while searching for some help, looks great!
Hopefully people will be on here when I need a nudge in the right direction as my tutor isn't available as much as I need him!
Thanks