im hoping that it will be the same as the last exam papers.. both of them are almost identical.. and there quite straight forward albeit with some parts ha.. you guys know more than me so don't worry
guys what about the Fourier transform of s(t) * thatoddsymbol (t)
where s((t) = pike 1 (t)
sorry for horrible use of english there
i get that it will be a square wave of width 1 from 0 to 1 convolving with a ?? i don't get that part. any ideas?
ha ahh I am so going to do that.. thanks alot. yeah i was just trying to visualise the question above with a negative component.. but the folding thing just confirmed what i already had. thanks a lot mate.. good luck for 242
thanks that explains alot. just a question with the drawing. if it had a negative component going down to -1 at t = .5 second would it still be an even function? would it still reflect across the x-axis or wouldn it reflect across both.. therefore making it an odd function.. i think I am...
can you clarify what you mean? do you mean there should be a negative component as well in the cos wave. that makes sense. i don't get why there is no negative part there. would the amplitudes be 1 and -1 respectively?
Firstly i meant to say .14mA not 1.4 V.
so that still leaves me with a final answer of Vo = 1.4 V
It makes a lot of sense what you saying.. i just need to work out Vo first. and that's where i have difficulty as I am not sure if my answer is correct.
Im positive however, that you can...
yep d2 starts conducting when the voltage across it is .7. so yeah the question is. what is the minimum voltage out for d2 to start conducting.
so i reasoned that the voltage across the 5k resistor would also be .7. so the current would be 1.4 along that wire.
from there i did took the...
Hey guys I am completely new to this site and electronics so forgive me. I've uploaded a photo of the question. I am trying to work out at what values does
just D1 conduct
D1 and D2 conduct
then finally all of them.
Im really stuck here. i know that the diodes start conducting when the...