Recent content by mack2014

  1. M

    Atwood pulley and calculating inertia based on slope (m)

    So I think I have figured it out... my acceleration is off, probably due to my time calculations. Therefore everything is off as Inertia should be a positive value not a negative value. Thank you both for your help. :)
  2. M

    Atwood pulley and calculating inertia based on slope (m)

    Thank you for the response, I am working through it now. We are actially given (m1 m2)g=(m1 +m2 + I/R^2 )a in the lab. The whole point of the lab is to derive this equation.. i just realize i posted m1 and m2 as the same number which they are not. The total mass (M) was 0.23385kg though...
  3. M

    Atwood pulley and calculating inertia based on slope (m)

    I thought that at first but my mass for m1 is 0.11975kg and m2 is 0.11975kg. They add to 0.23385kg which is much greater then .2109... I thought my graph may have been backwards, but the directions indicate that I am to plat (m1 - m2)g on the Y axis and acceleration on the x. Also, we aren't...
  4. M

    Atwood pulley and calculating inertia based on slope (m)

    Sorry. For some reason I keep trying to post and it only posts part of the first line. Trying again I am working on a lab that is meant to test the validity of (m1 m2)g=(m1 +m2 + I/R^2 )a . I created an Atwood pulley system. The system is accelerated due to the difference in weight on...
  5. M

    Atwood pulley and calculating inertia based on slope (m)

    I am working on a lab that is meant to test the validity of (m1
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