Recent content by mahoteacher

Oh I see that doesn't make sense now... So am I correct to think that for decay rate A = λN t½ = ln2/ λ => λ = 4.91932 * 10^ -18 [s^-1] Δ N = 6.022*10^23 [atoms/mol] / 238 [g / mol] = 2.530*10^21 [atoms/g] A = 12447 [s^-1] = 1.24*10^4 [s^-1] That value comes from the power value 1 mW =...

Thank you for correcting me my mistakes, and helping me to move the thread to the right place! E = Δ mass * c^2 E = 7.6106 *10^-30 *( 3*10^8)^2 = 6.84*10^-13 J Δ N = 6.022*10^23 [atoms/mol] / Δ amu [g/mol] = 7.9126* 10^-8 [atoms/g] Regarding the decay rate, I thought it means activity, which...

Homework Statement The masses of the following atoms are: 238 U → 238.050786(2) 234 Th→ 234.043598(5) 4 He → 4.002603 a) Calculate the energy available in the decay of 238U. b) Calculate the decay rate of 238U 238U half time = 4.468*10^9yrs c) If a block of uranium produces 1mW of power...