Recent content by Mainewriter

Eureka! One die would have the combinations: 0, 12; 1, 13; 2, 14; 3, 15; 4, 16; 5, 17 with the other die descending in the proper increments that 5 and 27 and always the beginning and ending points (ie, the last one would be 0, 2, 4, 6, 8, 10). So I am a little slow but finally the light bulb...

Ah...so if one die had 0, 0, 0 and 12, 12, 12 and the other die had 5, 7, 9, 11, 13, and 15 it would work. Every solution has the same probability of 1/12. Is there a formula for this? MW

If one die has a constant and the other die has the appropriate numbers, ie, the constant die has 0 and the other die could have 5, 7, 9, 11, 13, 15 or the constant die has 1 and the other has 4, 6, 8, 10, 12, 14 Am I on the right track? But I still get confused with 2 dice and 12 sums...

That is exactly my confusion. With the dice set up as I described, there is a 1/36 chance of rolling a five but 6/36 of rolling a 15. I don't understand how there could be the same probability for all numbers. MW

Homework Statement Given two unmarked, cubic dice and using the set of whole numbers, place numbers on each die such that only the following sums can be thrown: 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27 and the probability of rolling each sum is the same. Homework Equations The...