Recent content by mairzydoats

Are cartesian coordinates the only coordinates with a holonomic basis that's orthonormal everywhere?

Okay

When the cylinder is embedded, a secondary layer of bound densities is formed around it which oppose those of the P or M whose influence would otherwise be prevalent. That is why the method will measure H or D rather than E or B Too see what I mean you can try a thought experiment using my...

How so?

...which is model independent

...and so they are the usual assumptions for a good reason-they are the correct assumptions for the subject matter under discussion.

And besides, trying to discuss vector H on the quantum level doesn't even make any sense. H is defined as: H = B/μ° - M And M is by definition a macroscopic value. It is the magnetic dipole moment per unit volume. Undefined on the quantum level, and hence so too is H.

Yes, the usual assumptions in the macroscopic model.

The boundary condition which states that the discontinuity in the tangential component of the H at the border between two mediums is equal to the free surface current density J follows directly from the relation ∇ x H = Jfree + ∂D/∂t

But inside of a perfect conductor, there is no "polarization/magnetization" by definition. All charges/currents are "free charges/currents" and are at the surface. Where does choice come in? ...And what would you "shuffle" to change the conclusion you would be unavoidably directed to about...

Nope. https://en.wikipedia.org/wiki/Interface_conditions_for_electromagnetic_fields#Interface_conditions_for_magnetic_field_vectors At the interface between two mediums, the free surface current J is equal to the difference between the tangential components of H, on either side of the...

The only problem with saying H is just a mathematical construct and not a real field is that H can actually be directly measured by experiment at a particular point in space, and all without needing to know either B or M or even J locally. In this respect it is just as fundamental as E or B...

Can any polynomial in any degree of x be factored into a product of the form (leading coefficient)(x-a)(x-b) ... (x-z) as long as we can use complex numbers for a,b, etc.? Thanks

Thanks Geofleur. I thought so but just wasn't sure.

Hello I am trying to learn linear algebra, and I came across this definition of basis minor on this webpage: https://en.wikibooks.org/wiki/Linear_Algebra/Linear_Dependence_of_Columns "The rank of a matrix is the maximum order of a minor that does not equal 0. The minor of a matrix with the...