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Why do the centripetal and gravitational force equal each other in orbit?Also
Why do the centripetal and gravitational force equal each other in orbit??Also... Homework Statement Say for example, a problem wants us to find the mass of a planet. It gives us a satellite that orbits that planet with a radius of R and a period T. Now, I know how to solve this problem. You...- MakeItThrough
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- Centripetal Force Gravitational Gravitational force
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- Forum: Introductory Physics Homework Help
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Suppose that three astronomical objects
Homework Statement Suppose that three astronomical objects (1, 2, and 3) are observed to lie on a line, and that the distance from object 1 to object 3 is D. Given that object 1 has 1.5 times the mass of object 3 and seven times the mass of object 2, find the distance (in terms of D) between...- MakeItThrough
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- Replies: 1
- Forum: Introductory Physics Homework Help
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How Do You Calculate the Tension in a Lifting Cable Above a Worker?
thanks, i'll remember from now on to draw a free body diagram for Forces- MakeItThrough
- Post #10
- Forum: Introductory Physics Homework Help
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How Do You Calculate the Tension in a Lifting Cable Above a Worker?
Of course! Gravity! How could I forget? I'm not sure whether to add or subtract 0.620 from 9.8. Gravity is pulling down, while the acceleration of 0.620 is going upward. So it makes sense to subtract. FT = (94 kg + 153 kg) x (9.8 - 0.620) = 2267.46 ? *Edit That answer was wrong. So now I have...- MakeItThrough
- Post #8
- Forum: Introductory Physics Homework Help
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How Do You Calculate the Tension in a Lifting Cable Above a Worker?
that must be wrong then. The result I get is 153.14. The difference seems so little compared to my answer for part A...? What am i missing?- MakeItThrough
- Post #7
- Forum: Introductory Physics Homework Help
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How Do You Calculate the Tension in a Lifting Cable Above a Worker?
The acceleration is 0.620 m/s^2 upward. The tension of the cable above the worker the must be equal to the worker's mass AND also the mass of attached box below him times the acceleration. Ft = 94 + 153 x (0.620) is this correct?- MakeItThrough
- Post #6
- Forum: Introductory Physics Homework Help
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How Do You Calculate the Tension in a Lifting Cable Above a Worker?
If they are stationary, then acceleration would be zero and the net force would also be zero. So the tension of the cable above the worker would be equal to all the forces that are pushing the worker down. Right?- MakeItThrough
- Post #4
- Forum: Introductory Physics Homework Help
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How Do You Calculate the Tension in a Lifting Cable Above a Worker?
Homework Statement http://www.webassign.net/CJ/04_75.gif A cable is lifting a construction worker and a crate, as the drawing shows. The weights of the worker and crate are 922 and 1500 N, respectively. The acceleration of the cable is 0.620 m/s2, upward. (a) What is the tension in the cable...- MakeItThrough
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- Forces Friction
- Replies: 9
- Forum: Introductory Physics Homework Help
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Force Vectors: Find Horizontal Acceleration & Direction for 5.00-kg Block
Thank you! This is now starting to make sense! (left)- MakeItThrough
- Post #5
- Forum: Introductory Physics Homework Help
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Force Vectors: Find Horizontal Acceleration & Direction for 5.00-kg Block
ahh I figured it out. F1x is 12.68 N and F2 is 45.5 N. I just subtract 12.68 from 45.5 and that gives me 32.82 N. The mass of 5 kg is given. Plugging this into the formula F=ma 32.82 / 5 kg = 6.564 m/s^2. However, I'm not sure which direction the horizontal acceleration goes. Left or Right? How...- MakeItThrough
- Post #3
- Forum: Introductory Physics Homework Help
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Force Vectors: Find Horizontal Acceleration & Direction for 5.00-kg Block
Homework Statement http://www.webassign.net/CJ/04_11.gif Two forces, F1 and F2, act on the 5.00-kg block shown in the drawing. The magnitudes of the forces are F1 = 30.0 N and F2 = 45.5 N. What is the horizontal acceleration (magnitude and direction) of the block? Direction... Left or Right...- MakeItThrough
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- Force Vectors
- Replies: 4
- Forum: Introductory Physics Homework Help
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Help with this problem : Projectile Motion
Thanks for your help! I got it! There are two values for t. One of them is the motion of the bullet to the window. The other is the motion to the wall that the bullet hit. what I did was set t = D/340 for motion to the window. Then I made an equation regarding H and plugged in the value for...- MakeItThrough
- Post #3
- Forum: Introductory Physics Homework Help
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Help with this problem : Projectile Motion
Homework Statement http://www.webassign.net/CJ/3-45alt.gif ... (y = 0.46 m, and x = 6.6 m.) From the top of a tall building, a gun is fired. The bullet leaves the gun at a speed of 340 m/s, parallel to the ground. As the drawing shows, the bullet puts a hole in a window of another building and...- MakeItThrough
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- Motion Projectile Projectile motion
- Replies: 3
- Forum: Introductory Physics Homework Help