Recent content by mananvpanchal

I can't get the all. First you said the rod is stretched under force. And second you said .

In this scenario length is not going to alter by force applied on the object. I am guessing that force applied at all points of the component so it will not be alter. So, here no issue about alteration. What I understand from your quote that component is actually stretched by applied...

Can you please explain me little more. If it was small boost then will the length be contracted suddenly or will it be a slow process by the traveling time?

Perfect. But, I have a question. If we give a velocity boost on every component part of an object at the same time in one inertial coordinate system then do the object become length contracted in the same inertial coordinate system after changing its velocity?

Please, look at below image. Red dot show events on andromeda worldline. Observer A's worldline is shown in green color. Observer B's worldline is shown in blue color who is start traveling at some time. A's LoS shown in green color and B's in blue. Before start traveling observer A and B are...

Yes, Because, that red events occurred at andromeda are outside of the light cone on "travelling start" event on observer's world line. So, that red events can't effect or to be not affected by "travelling start" event. There is no relation between its. So we can arrange LoS of combined frame...

Hello durant, You can see in first image that red events on andromeda occurs for the observer before start travelling. At some point observer start traveling and its seems that the same red events are reoccurring for the obeserver on andromeda. This seems a paradox. But, its isn't...

Front pulse has to travel more journey than rear pulse. Because, front pulse is traveling in the same direction, and rear pulse traveling against. In return journey of pulse, rear pulse has to travel more distance than front. Pulse reaches at center simultaneously for both observer.

Ok... Thanks guys.. for detailed explanation.

DaleSpam, Doc Al, GAsahi The A and B starts simultaneously and continue with simultaneous constant acceleration in C's frame. But, not in spaceship's frame. The simultaneous changes of speed in C's frame remains spaceships at constant distance in C's frame. The distance remains equals for all...

Hello, Suppose, A and B spaceships are moving with constant acceleration. There is a string tied to spaceships center to center. A is on left of B and B is on right of A. C is outside observer. As speed increase, A sees that B going further ahead, and B sees A going further behind. So, from...

You can see in above image that B is going far from A. So, B's Line of present touches to A's past. And C is coming near to A. So, C's LoP touches to A's future. But, this is just the game of words. C cannot see A's future before A. B cannot do anything in A's past to affect A's present...

Time dilation would be applied for other FoR, not your. Brain processing speed has nothing to do with light speed. Brain processing speed is too slow than light speed. How brain works: Light comes into eye with some image. The image is created to retina. After clearing the image...

Thanks harrylin. Thanks yuiop.

Ok, If there are two intensity detector at front of light source and end of light source in light source's frame. And same two detector in observer's frame. Will the source's detectors measure equal intensity? And observer's detectors measure unequal intensity?