Recent content by manasi bandhaokar

Yeah... Thank you.

Err... I am not going to any coaching class or college. I have taken a drop for engineering entrance and self studying.

Oh no! My bad! I am sorry ! U r right . I meant D. Yeah I am also getting C as P. It's again the messed up origin of paper setters. I think that settles the question. Thanks for all your help everyone. And that for bearing with me.

Yes to C. If what I have reasoned is right, the eqn for graph if C should be w+mg . it is independent of B. So it should be a straight line parallel to X axis.

Well but , as u said I was right about the only effect of addition of block being rise in water level and that it leads to force on the bottom which is w + B (reading of electronic scale) . and we know that reading of spring balance is mg - B , the sum of the readings is w+mg (constant) . so...

The correct ans is A-R, B-Q , C-S , D -T. And I am getting A -Q , B-R.

Yeah I get that. But it's said that the INITIAL position is h = h° . when we consider the ref point as you considered , the initial position is h= 0. Probably the paper setters messed up with the origin so that the question says something and options say the opposite , that's why my ans doesn't...

The correct matching(ans) is the one you got. But haven't they clearly specified h. And the way they have defined it means it's decreasing as block lowers

But it's given that h is distance between bottom of vessel and bottom of cube which is decreasing!

So kx = mg - B . as the block is lowered the the reading is constant from h° to b. Then B starts increasing and the reading decreases too, as h decreases from b to b-a. After that the B is constant till h becomes 0. If you put all this together , you get Q as ans not R , where clearly as h is...

OK thank you very much to everyone.

Yeah! But I was getting A -Q and B- R.I can see why I was getting B wrong -I had got the force wrong then. But I had taken spring balance reading as mg -B . still I got it wrong. I will try it once more.

So we count that the only effect of putting the block is rise if water level that changes the force on the base. Nothing else? No other effect?

Err... Alright.

I think I get it... Please verify if I am right The effect of adding the block is that the level of water level rises in the tank. Rise of water level is (a^3)/A. A is area of base of tank. Hence force on the bottom is- [dg(b + (a^3)/A]A (d- density of water) =dgbA + dg(a^3) = w + B (I think...