Recent content by mandymandy

Use integration to find the area of the region bounded by the given polar curves r = \frac{3}{(1+cos \theta )} and \theta = \frac{\pi}{2} A = \frac{1}{2} \intf(\theta)^{2}d\theta My attempt: (from -\frac{-\pi}{2} to \frac{\pi}{2} ) A = \frac{1}{2}\int...

I can solve it from here I don't know why I was so confused. :) thanks

Homework Statement Carrying capacity N of a population Assume: small population, dp/dt is proportional to P if 0<P<N then p(t) increases if P>N then P(t) decreases equilibrium means dp/dt = 0 Homework Equations dP/dT = KP(N-P) Solve for P(t) The Attempt at a Solution...