There is asymptotic potential in the form of some ln function. But I don't know how to calculate it. and regarding potential at y(0), i will recheck my solution.
But my question is that if I have a solution for this differential equation at initial conditions, how can i get an asymptotic...
This is the nonlinear equation
diff(y(r),r,r)+2*diff(y(r),r)/r+486*polylog(3/2,-exp(1-1/43*y(r))) = 0;
Initial conditions: y(0) = 0, D(y)(0) = 0.
Sol:1.05375994-.2150397042*r+.2150397042*r^2
Thank you
I have the solution (a potential) for a nonlinear differential equation found at r=0. How can I calculate the asymptotic potential at r->infinity?
Thanks in advance
MS
I have the solution (a potential) for a nonlinear differential equation found at r=0. How can I calculate the asymptotic potential at r->infinity?
Thanks in advance
MS