Recent content by Marcell

Thanks for explaining it so many times, I think I finally got it, have a good one!

ah I see what you mean. No, sorry for the confusion, but that is not the data I have (object doesn't reach terminal velocity), either way I really appreciate your time and effort thanks!

taking $$v=ah+b,$$ $$\frac{d}{dh}\left(mgh-\frac{1}{2}m(ah^2+2\operatorname{abh}+b^2\right))$$ then $$F=\left(mg-\frac{1}{2}m\left(2ah+2ab\right)\right)$$ And from that, as h increases, F decreases which doesn't make sense.

Well the slope doesn't change too much if it all, it appears to be linear. Also I don't quite see why differentiating ##\frac d{dh}(gh-\frac 12v^2)## _wouldn't_ lead to a drag force which decreases with velocity.

Where does gh come from? ##\frac d{dh}(mgh)=mg## no? please correct me if I'm wrong.

That is quite interesting, but I don't think I could do it since I only have one pair of ##(T_1,V_1)##, after all the whole experiment is done with a single object. Down is positive, so both v and dv/dh are positive

Wait, doesn't this equation suggest that as velocity increases the force of drag acting on the object decreases? There's no way that can be right...

Eyyyy, thank you so much, I got it! Squared the line of best fit's equation and then just took its derivative.

Wait I'm quite confused, wouldn't the right hand side just equal ##mg##? The only way I see getting a non-constant force of drag would be if the right hand side were differentiated with respect to v (though that doesn't make too much sense to me...)

I'm not sure if I follow, but I don't want to find v(t), I'm looking for ##F_{drag}## and I don't have the form of ##F_{drag}##...

Distance. I get the force done on the body. However, differentiating ##W(air~drag)=mgh-\frac{1}{2}mv^2,## with respect to s (s=h), got me ##0=mg##

Wait, even if I do differentiate it with respect to something, wouldn't here only be one component on the left hand side? and would said component then be equal to zero?

distance? Would that give the instantaneous work being done on the falling object and allow me to find the force of drag? If so I'm really not sure how to differentiate something like that, and my go to 'derivate-calculator.com' is lost here as well.

Thanks for the help! But I don't quite see how solving for the time taken to reach terminal velocity ##T## would be useful in finding the drag force acting on the object at a specific velocity...

Homework Statement The final velocity of an object falling through air from various heights is given. From this, can you derive an equation for the drag force acting on the object with respect to velocity? Homework Equations Maybe relevant? Wno drag$$=mgh,$$ Wreal$$=\frac{1}{2}mv^2,$$...